Hello help me with this question thanks in advance


Hello help me with this question thanks in advance

brookebeatrice8 brookebeatrice8    3   14.02.2022 03:00    4

Answers
hahHcjckk hahHcjckk  14.02.2022 03:00

\bold{\huge{\green{\underline{ Solutions }}}}

Answer 11 :-

We have,

\sf{HM = 5 cm }

In square all sides of squares are equal

The perimeter of square

\sf{ = 4 × side }

\sf{ = 4 × 5 }

\sf{ = 20 cm }

Thus, The perimeter of square is 20 cm

Hence, Option C is correct .

Answer 12 :-

We have,

\sf{MX  = 3.5 cm }

In square, diagonals are equal and bisect each other at 90°

Here,

\sf{MX  = MT/2}

\sf{MT = 2 * 3.5 }

\sf{MT = 7 cm}

Thus, The MT is 7cm long

Hence, Option C is correct .

Answer 13 :-

We have to find the measure of Angle MAT

All angles of square are 90° each

From above

\sf{\angle{MAT  = 90° }}

Thus, Angle MAT is 90°

Hence, Option B is correct .

Answer 14 :-

We know that,

All the angles of square are equal and 90° each

Therefore,

\sf{\angle{MHA  = }}{\sf{\angle{ MHT/2}}}

\sf{\angle{MHA = 90°/2}}

\sf{\angle {MHA = 45°}}

Thus, Angle MHA is 45°

Hence, Option A is correct

Answer 15 :-

Refer the above attachment for solution

Hence, Option A is correct

Answer 16 :-

Both a and b

The median of isosceles trapezoid is parallel to the baseThe diagonals are congruent

Hence, Option C is correct

Answer 17 :-

In rhombus PALM,

All sides and opposite angles are equal

Let O be the midpoint of Rhombus PALM

In ΔOLM, By using Angle sum property :-

\sf{35° + 90° + }{\sf{\angle{ OLM = 180°}}}

\sf{\angle{OLM = 180° - 125°}}

\sf{\angle{ OLM = 55° }}

Now,

\sf{\angle{OLM = }}{\sf{\angle{OLA}}}

OL is the bisector of diagonal AM

Therefore,

\sf{\angle{ PLA = 55° }}

Thus, Angle PLA is 55° .

Hence, Option C is correct


Hello help me with this question thanks in advance
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