Given r(x)= -5-x and s(x)=x²-8, which of the following is equivalent to t(x)=s(r(x)) a) t(x)= x²+10x+17
b) t(x)= -x²+3
c) t(x)= -x²-13
d) t(x)= x²-10x+3
e) None of the above

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Mathematics: Given r(x)= -5-x and s(x)=x²-8, which of the following is equivalent to t(x)=s(r(x)) a) t(x)= x²+10x+17b) t(x)= -x²+3c) t(x)= -x²-13d) t(x)= x²-10x+3e) None of the above

Nason156 · Answer

The answer would be s(r(x)) = -8 + (-8 + x² )²...

Given r(x)= -5-x and s(x)=x²-8, which of the following is equivalent to t(x)=s(r(x)) a) t(x)= x²+10x+17b) t(x)= -x²+3c) t(x)= -x²-13d) t(x)= x²-10x+3e) None of the above

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Given r(x)= -5-x and s(x)=x²-8, which of the following is equivalent to t(x)=s(r(x)) a) t(x)= x²+10x+17
b) t(x)= -x²+3
c) t(x)= -x²-13
d) t(x)= x²-10x+3
e) None of the above