Jamie has a rectangular pool that has a length of 12 feet and a perimeter of 40 feet. What is the width of the pool?

raekwon12 raekwon12    3   14.02.2022 07:50    5

Answers
blueberrybaby1 blueberrybaby1  14.02.2022 07:50
8 feet

Step-by-step explanation:

Given,

Perimeter of a rectangular pool (P) = 40 feet

Length of the pool (l) = 12 feet

Let,

Width of the pool be = w

As we know,

Perimeter of a rectangle = 2(length + width)

Therefore,

By the problem,

=> 2(l + w) = P

[On substituting the values of l = 12 and P = 40]

=> 2(12 + w) = 40

[On multiplying 2 with 12 and w]

=> 24 + 2w = 40

[On subtracting both sides with 24]

=> 24 - 24 + 2w = 40 - 24

[On Simplifying]

=> 2w = 16

[On Dividing both sides with 2]

=> \frac{2w}{2} = \frac{16}{2}

[On Simplifying]

=> w = 8

Hence,

The required width of the pool is 8 feet. (Ans)

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micro7909 micro7909  14.02.2022 07:50

The Width of the pool would be 8 feet/ft. .

Step-by-step explanation:

According to the Question Given:

Perimeter = 40 ft/feet

Length of the pool = 12 ft/feet

To Find:

The width/breadth of the pool

Solution:

We know that,

\boxed{\tt \: Perimeter \:  of  \: Rectangle = 2(l + b)}

So Put their values accordingly:

Perimeter of The Rectangle = 40Length[L] = 12

\longrightarrow \tt \: 40 = 2(12 + b)

We got an equation.By this method we can easily find the breadth/width of the pool.

Solve this equation:

\longrightarrow \tt40 = 2b + 24

Flip the equation:

\longrightarrow  \tt2b + 24 = 40

Transpose 24 to the RHS[remember to change its sign]:

\longrightarrow \tt2b = 40 - 24

Simplify:

\longrightarrow \tt2b = 16

Divide both sides by 2:

\tt\longrightarrow \cfrac{2b}{2}  =  \cfrac{16}{2}

Use Cancellation method and cancel LHS and RHS:

\tt\longrightarrow \cfrac{ \cancel2 {}^{1} b}{ \cancel2}  =  \cfrac{ \cancel{16} {}^{8} }{ \cancel2}

\longrightarrow \tt1b = 8

\longrightarrow \tt{b} =\boxed{\tt  8 \: feet}

Hence, the breadth/width of the pool would be 8 ft./feet .

\rule{225pt}{2pt}

I hope this helps!

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